I got bored and fixed it :x

#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;

void instructUser()
{
        cout << "                    " <<endl;
        cout << "  ***************************************************************************" <<endl;
        cout << "  *  This program takes your input and selected mathematical operator       *" <<endl;
        cout << "  *  and returns the answer to the screen. If an illegal operator is        *" << endl;
        cout << "  *  selected, an error message will be displayed. Be careful which         *" <<endl;
        cout << "  *  operator you select because the program depends on you for input.      *" <<endl;
        cout << "  *  The only error check function it has, is for unacceptable opreators.   *" <<endl;
        cout << "  *  Acceptable operators are : (+ , - , / , * ,^,c). The character c sets  *" <<endl;
        cout << "  *  the value stored to ZERO. Enter Q to exit. ENJOY YOUR PROGRAM !!!!!!   *" <<endl;
        cout << "  ***************************************************************************" <<endl;
        cout << "                     " <<endl;
} 
int main()
{
    instructUser();
    double displayedVal;
    double newEntry;
    char command_character = 'C'; 
    displayedVal = 0.0;
    cout << "  Enter a number: " ;
    cin >> displayedVal;
    cout << "  Enter accepted Operator: " ;
    cin >> command_character;
    while (command_character != 'Q' || command_character != 'q')
    {
        switch(command_character)
        {
        case 'c':
        case 'C': displayedVal = 0.0;
                  break;
        case '+': cout << "  Enter a number: ";
                  cin >> newEntry;
                  displayedVal = displayedVal + newEntry;
                  break;
        case '-': cout << "  Enter a number: ";
                  cin >> newEntry;
                  displayedVal = displayedVal - newEntry;
                  break;
        case '*': cout << "  Enter a number: ";
                  cin >> newEntry;
                  displayedVal = displayedVal * newEntry;
                  break;
        case '/': cout << "  Enter a number: ";
                  cin >> newEntry;
                  do if (newEntry == 0)
                  {
                      cout << "  You cannot devide something by 0" << endl;
                      cout << "  Enter a number: ";
                      cin >> newEntry;
                  } while (newEntry == 0);
                  displayedVal = displayedVal / newEntry;
                  break;
        case '^': cout << "  Enter a number: ";
                  cin >> newEntry;
                  displayedVal = pow (displayedVal,newEntry);
                  break;
                  default : cout << "  Unacceptable Operator(" << command_character << ")" << endl;
        }
        cout << "  The result so far is: " <<displayedVal<< endl;
        cout << "  Enter Operator: ";
        cin >> command_character;

    }
    system ("pause");
    return 0;
}

error C2144: syntax error : 'double' should be preceded by ')'

if (newEntry == 0)
{
     doDivideZero(double &);
}

if you're wondering why you can't compile it, its because your not passing any variable in doDivideZero()

i have no idea what is wrong

Did you write this? You can only post tested, working code of your own.