By FLCL on Oct 26, 2007$iseven returning $true if the string is even.
$isodd returning $true if the string is odd.
/*
$iseven & $isodd checks if the number is odd or even.
If the number is even it returns $true, (and for $isodd) if the number is odd it returns $true.
; Syntax:
$iseven(string)
$isodd(string)
; Shoutouts:
Olliegod & jaytea - helped me simplify a horribly written code. Thanks guys.
*/
alias iseven return $iif(2 // $1,$true,$false)
alias isodd return $iif(!$iseven($1),$true,$false)
/*
$iseven & $isodd created by FLCL
Unauthorized editing/redistribution of this script is forbidden.
*/
there\'s lots of ways to accomplish this, FLCL\'s methods are probably amongst the worst i\'ve seen (sorry, just seems like you\'ve copied techniques without understanding them at all :P), here\'s quite possibly the shortest method:
Nope. I fully understand this snippet. I guess it\'s just my habit to over complicate things with $regex. I am going to reduce the code a bit more right now. Hopefully it won\'t be as bad as it was before.
I\'ll probably go with something similar to $iif(2 // $1) as you pointed out jaytea.
not quite Olliegod :P $1 // 2 checks $1 is a factor of 2. you want the reverse, 2 // $1
there\'s lots of ways to accomplish this, FLCL\'s methods are probably amongst the worst i\'ve seen (sorry, just seems like you\'ve copied techniques without understanding them at all :P), here\'s quite possibly the shortest method:
alias iseven return $isodd($calc($1 -1))
alias isodd return $istok(1,$and($1,1),0)
there\'s a lot of other conditions you can use to check $1 is odd/even :P
if ($1 & 1) ; odd
if ($1 !& 1) ; even
if (1 \\\\ $calc($1 / 2)) ; odd
if (1 // $calc($1 / 2)) ; even
if ($calc($1 % 2)) ; odd
if (!$calc($1 % 2)) ; even
if ($1 == $or($1,1)) ; odd
if ($1 != $or($1,1)) ; even
and the list goes on :P
